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2 years ago

Please help :C I've been absent for the past few days

Mathematics

1 answer:

jarptica [38.1K]2 years ago

7 0

Answer:

I believe it's d ?

Step-by-step explanation:

I'd definitely do some research on "similar triangles"

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Consider the half of the sphere of radius 2 centered at the origin which lies above the xy-plane (a hemisphere). Suppose the den

Harlamova29_29 [7]

Answer:

25.133 units

Step-by-step explanation:

Since the density ρ = r, our mass is

m = ∫∫∫r³sinθdΦdrdθ. We integrate from θ = 0 to π (since it is a hemisphere), Φ = 0 to 2π and r = 0 to 2 and the maximum values of r = 2 in those directions. So

m =∫∫[∫r³sinθdΦ]drdθ

m = ∫[∫2πr³sinθdθ]dr ∫dФ = 2π

m = ∫2πr³∫sinθdθ]dr

m = 2π∫r³dr ∫sinθdθ = 1

m = 2π × 4 ∫r³dr = 4

m = 8π units

m = 25.133 units

5 0

3 years ago

Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

saul85 [17]

Answer:

$P(x,y) = (0,\frac{11}{5})$

Step-by-step explanation:

Given

$A = (-2,1)$

$B = (3,4)$

$m:n = 2:3$

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

$P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

Where

$(x_1,y_1) = (-2,1)$

$(x_2,y_2) = (3,4)$

$m:n = 2:3$

This gives:

$P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})$

$P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})$

$P(x,y) = (\frac{0}{5},\frac{11}{5})$

$P(x,y) = (0,\frac{11}{5})$

5 0

3 years ago

Finding co-ordinates using equations. Please help and explain how I would solve these equations, to plot on a graph, to answer t

Misha Larkins [42]

Step-by-step explanation:

I don't know if this helps but there is an app call symbols which is free which maybe it can help you to grapgh.

6 0

3 years ago

A shipping company charge $15 to ship a package and 5% the shipping charge for the shirts on the package what was a total cost t

Advocard [28]

15.75 out of my math

3 0

3 years ago

Read 2 more answers

The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?

Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are $(x_{1}, y_1)$ and $(x_2, y_2)$ then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

$(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})$

Thus for our question the endpoints are $(x_E, y_E)$ and $(x_F, y_F)$ and hence the midpoint will be:

$(x_M, y_M)=$ $(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})$

Thus, Option C is the correct option.

6 0

4 years ago