Is this the sqrt root of ((1.16x10^-19)^2)
5x-3=21-x
6x=24
X=4
You simply have to isolate the variable and then divide by 6 so that x is completely alone.
7 because 7 • 7 = 49 • 7 = 343
Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
b² = 225
b = 15
Answer: the length of the common external tangent is 15.
![\sqrt[8]{48^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B48%5E4%7D%20)
can be rewritten as

to the

power:

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

This is equivalent to

, so now, we just simplify:

So: