We are given with a bag containing 13 dark chocolates, 16 white chocolates, and 11 milk chocolates. hence the sample space is 13 + 16 + 11 equal to 40 chocolates. The <span> probability that she randomly picks a white chocolate is 16/40 or 2/5 and that she picks a milk chocolate is 11/40. Hence the probability of picking either is (16+11) /40 equal to 27/40</span>
Option A. is correct for the given condition.
Lets solve it through steps of range and functions,
First of all, Solve the equation:
(1)
(2)
So these would be the ranges of X in between 5 and -5.
Hence option A. 
is correct.
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Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
I solved this like you would a system of equations - if that is not the answer you need LMK
Point form:
(- 1/11, 32/11)
Equation Form:
x = -1/11, y = 32/11
Step-by-step explanation:
Answer:
1/7 or 14.3%
Step-by-step explanation:
30% of 750 = 225 (females who study chemistry)
60% of 2250 = 1350 (males who study chemistry)
1575 = total students studying chemistry
P (female chemistry student) = 225/1575 = 1/7 (simplified)
1/7 = 14.3%
