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Maru [420]
3 years ago
5

Find the equation of the line. Use exact numbers

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

It would be y=2x+4 since the slope is 2 and the y-intercept is 4

(your welcome!)

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(-4, -2); y = - 2x + 4
padilas [110]

Answer:

y = -2x - 10

Step-by-step explanation:

Slope intercept form of equation is of form

y = mx+c

where m is the slope of line and c is the y intercept of the line.

Y intercept is point on y axis where the line intersects the y axis.

_____________________________

Given equation

y = -2x +4

comparing it with y = mx+ c

m = -2 , c = 4

_____________________________

when two lines are parallel, their slopes are equal.

Let the equation of new line in slope intercept form be y = mx + c

Thus slope of of new required line is -2

Thus m for new line is -2.

now, equation of required line : y = -2x+c

Given that this line passes through (-4, -2). This point shall should satisfy equation  y = -2x+c.

Substituting the value of (-4, -2) we have

-2 = -2(-4)+c

=> -2 = 8 +c

=> -2 -8 = c

=> c = -10.

Thus , equation of required line is  y = -2x - 10.

8 0
3 years ago
The solution is <br><br> u = ?
Tpy6a [65]

Answer:

u = (b/hn)

Step-by-step explanation:

The inverse!!

3 0
1 year ago
What does gemdas and pemdas stands for?
DanielleElmas [232]

Answer:

For pemdas

P Parentheses

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

And for gemdas

G Grouping

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

8 0
3 years ago
Read 2 more answers
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
Write one hundred and fourteen thousandths as a decimal number.
Zarrin [17]

Answer:

0.114

Step-by-step explanation:

hope this help :)

8 0
3 years ago
Read 2 more answers
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