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3 years ago

The probability for four different simple events are given of the four which is least likely to occur

Mathematics

1 answer:

sveticcg [70]3 years ago

6 0

The decimal that has the lowest number is the one least likely to occur

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A hot air balloon went from an elevation of 4,064 feet to an elevation of 3,322 feet in 28 minutes. What

ELEN [110]

Answer:

<em>The air balloon descends 26.5 feet per minute</em>

Step-by-step explanation:

<u>Rate of Change</u>

The rate of change is a measure that compares two quantities, usually to know how one variable changes in time.

The hot air balloon was 4,064 feet high and, 28 minutes later, it went to 3,322 feet. We can calculate the rate of descent R by dividing the change of elevation over time:

$\displaystyle R=\frac{3,322-4,064}{28}=\frac{-742}{28}=-26.5$

Thus the air balloon descends 26.5 feet per minute

3 0

3 years ago

Hot dogs at a carnival cost $2.99 each plus 7% tax. What is the total cost for one hot dog?

marysya [2.9K]

$2.99 + 7% of $2.99 =

= $2.99 + 7% * $2.99

= $2.99 + 0.07 * $2.99

= $2.99 + $0.21

= $3.20

4 0

3 years ago

Read 2 more answers

Which transformation could NOT be used to prove that two circles are congruent to one another?

EleoNora [17]

Answer: D

Step-by-step explanation:

6 0

2 years ago

Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx

yawa3891 [41]

$\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}$

Expand the numerator as

$x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2$

Then in the limit,

$\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}$

3 0

3 years ago

Please solve equations by completing square

BlackZzzverrR [31]

$x^2-4x+1=0\\
x^2-4x+4-3=0\\
(x-2)^2=3\\
|x-2|=\sqrt3\\
x-2=\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3$

$x^2+6x-9=0\\
x^2+6x+9-18=0\\
(x+3)^2=18\\
|x+3|=\sqrt{18}=3\sqrt2\\
x+3=3\sqrt2 \vee x+3=-3\sqrt2\\
x=-3+3\sqrt2 \vee x=-3-3\sqrt2\\$

$x^2+20x+3=0\\
x^2+20x+100-97=0\\
(x+10)^2=97\\
|x+10|=\sqrt{97}\\
x+10=\sqrt{97} \vee x+10=-\sqrt{97}\\
x=-10+\sqrt{97} \vee x=-10-\sqrt{97}$

$x^2-2x-5=0\\
x^2-2x+1-6=0\\
(x-1)^2=6\\
|x-1|=\sqrt6\\
x-1=\sqrt6 \vee x-1=-\sqrt6\\
x=1+\sqrt6 \vee x=1-\sqrt6$

8 0

3 years ago