Question

A player in a board game will roll two standard dice. She needs to roll a 9, 10, or 11 to win the game. Determine the sample space for the number of ways two dice can come up and drag and drop the correct numbers to complete the statement. Since the sample space consists of a total of 36 ways two dice can come up, there is a ----% chance that the player will roll a 9, 10, or 11 and win the game.

Answer 1

Answer:

$25\%$

Step-by-step explanation:

$Sample\ Space=Possible\ outcomes\\=\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1)(4,2),(4,3),(4,4),(4,5),(4,6)\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}\\\\Total\ possible\ outcomes=36\\\\Favourable\ outcomes=9,10\ or\ 11=\\\{(3,6),(4,5),(4,6),(5,4),(5,5),(5,6),(6,3),(6,4),(6,5)\}\\\\Number\ of\ favourable\ outcomes=9$

$Percentage\ chance\ to\ win=\frac{favourable\ outcomes}{total\ outcomes}\times 100\\\\Percentage\ chance\ to\ win=\frac{9}{36}\times 100=\frac{100}{4}\\\\Percentage\ chance\ to\ win=25\%$