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Dima020 [189]
3 years ago
14

Hi. hihihihihihihihi

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
Hi hi hi hi hi hi hi hi hi hi hi.... Hey
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Brenda observes that the keyboard and the screen of an open laptop lie on two different planes. In how many lines do the planes
Citrus2011 [14]
Answer: 1

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Explanation:

The keyboard and screen can be thought of as flat rigid sheets of paper. They are joined along one single line which is where the hinge is located. Any two planes intersecting will form a single straight line assuming these planes are not parallel to one another.

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AYOOOOOOOOOO HELP PLESE WILL GIBE BRAINLIST
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Answer:

15 rooms

Step-by-step explanation:

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36.  
Burka [1]
Area 1st rectangle = 10 * 7 = 70 cm^2
length of 2nd rectangle is 2*7 = 14 cm

Area 2nd = 10 * 14 = 140 cm^2

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The 2nd triangle was twice as big as the 1st.  Answer A
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3 years ago
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Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
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