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faust18 [17]
2 years ago
10

Which shape listen below will result from cross section b?

Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0

Answer: Ellipse

This cross section is not parallel to the circular base, so we get a stretched out circle of sorts. In other words, we get an ellipse.

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Of the following sets, which represents a function? Situation A = {student's name, all the colors that the student likes} Situat
luda_lava [24]

Answer:

Situation A

Step-by-step explanation:

please mark as brainlist answer

8 0
2 years ago
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Indicate whether or not 1/√2 belongs to each set of numbers<br><br>​
Oksi-84 [34.3K]

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6 0
3 years ago
A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat
Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

Step-by-step explanation:

1) Data given and notation

s^2 =16 represent the sample variance

s=4 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=36.191

\chi^2_{1- \alpha/2}=7.633

And replacing into the formula for the interval we got:

\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}

8.400 \leq \sigma^2 \leq 39.827

So the 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

7 0
3 years ago
A student has $1 bills and $5 bills in his wallet. He had a total of 15 bills that are worth $47. How many of each type does he
Mrrafil [7]

Total number of $1 bills=7

Total number of $5 bills=8

Further explanation:

Given

Let x be the number of $1 bills

and

y be the number of $5 bills

Then according to the given statements

x+y=15

x+5y=47

From first equation:

x+y=15\\x=15-y

Putting x=15-y in second equation

x+5y=47\\15-y+5y=47\\4y=47-15\\4y=32\\\frac{4y}{4}=\frac{32}{4}\\y=8

Putting y=8 in first equation

x+8=15\\x=15-8\\x=7

Hence,

Total number of $1 bills=7

Total number of $5 bills=8

Keywords: Linear equations, Substitution method

Learn more about linear equations at:

  • brainly.com/question/2367554
  • brainly.com/question/2977815

#LearnwithBrainly

4 0
3 years ago
On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d
Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

                         X~ N ( 67.2 , 4.6^2 )

Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

6 0
3 years ago
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