Check the picture below.
the triangle has that base and that height, recall that A = 1/2 bh.
now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,
so, add AC + AB + CB, and that's the perimeter of the triangle.
The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area = 
x 9 x 12
= 54
Answer:
=(-1,-5)
Step-by-step explanation:
y=X1=4
y=-2x-5-2
Answer:
x = 3/4
Step-by-step explanation:
The lowest common denominator is 4(x + 2) so we multiply each side by this:
3 = 4x
x = 3/4.
Answer - The difference between two positive integers can be either positive, negative or zero. When the first positive integer is larger than the second positive integer in a subtraction problem, the difference will be positive.
Note: 0 is neither positive nor negative
