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disa [49]
3 years ago
15

you have $15,000 to invest for 5 years at 5.5% annual interest rate that is compounded continuously. how much money will you hav

e at the end of 5 years?
Mathematics
1 answer:
MissTica3 years ago
4 0

Answer:

$19,747.96

Step-by-step explanation:

You are going to want to use the continuous compound interest formula, which is shown below:

A = Pe^{rt}

<em>A = total</em>

<em>P = principal amount</em>

<em>r = interest rate (decimal)</em>

<em>t = time (years)</em>

<em />

First, lets change 5.5% into a decimal:

5.5% -> \frac{5.5}{100} -> 0.055

Next, plug in the values into the equation:

A=15,000e^{0.055(5)}

A=19,747.96

After 5 years, you will have $19,747.96

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devlian [24]

Answer: the answer is X=8


Step-by-step explanation:


3 0
3 years ago
I cannot figure out how to do these two questions. If someone could please show me step by step that would be awesome. Thanks in
Korvikt [17]
So angles in a triangle add up to 180
Angle B is 50 and angle E is 90

90+50=140
180-140=40°(angle A)

Now the other triangle
Angle C is 62 and angle E is 90

90+62=152
180-152=28

40-28=12
hope this helped but I can't help with the second one
5 0
4 years ago
David walked for 20 minutes with the speed of 3 mph. How far did he walk?<br><br>HELP!!!
Ludmilka [50]

Answer:

1 mile

Step-by-step explanation:

1 hour = 3 miles

20 minutes is 1/3 of an hour, so he walks 1 mile

7 0
3 years ago
Let X represent the SAT score of an entering freshman at University X. The random variable X is shown to have a N(1200, 90) dist
Lelechka [254]
The correct answer to this question is 0.1456. This is <span>the probability that X bar will be greater than Y bar. </span>Probability is the measure of how likely an event is. The formula is the ratio of the number of favorable outcomes to the total number of possible outcomes. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
4 0
4 years ago
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. at the same inst
77julia77 [94]

You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²

At the same time, a truck moving speed o 8.50 m/s passes the car

D=v.t (for the truck)

And d= v.t+1/2.a.t²(for the car)

v.t=1/2.a.t²

t=2.v/a

t=2.8.50 m/s/ 2.70 m/s²

17m/2.70=6.29

This mean that the distance is  

D=v.t=8.50m/s.6.29= 53.465 m/s

The speed of the car is  

Vcar=a.t

2.7m/s2×× 53.65

=144.34


4 0
3 years ago
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