Given :
a-b = c-d ...1)
b = d-1 ...2)
c = 6
To Prove :
a = 5
Solution :
Adding equation 1 and 2, we get :
(a-b) + (b) = (c-d) + (d-1)
a = c -1 ...3)
Putting given value of c = 6 in above equation, we get :
a = 6 - 1
a = 5
Hence, proved.
If you are already given the general solution, finding the particular solution means to impose some conditions in order to fix the coefficients of the general solution.
The first thing we need to impose is that the function must output -1 when the input is zero. So, if we plug zero as input we have

But we want
, which implies 
So, we fixed the first coefficient. To fix the second one, we can use the second piece of information (and of course the already-found value for
).
We want the first derivative to output 3 when the input is zero. So, first of all, let's compute the first derivative, and evaluate it in zero:


And as before, since
and we want
, we deduce
.
So, once we fix both coefficients, the general solution becomes

Answer:
on what? I will, but on what?
Answer:
H V
1 4π
2 8π
3 12π
There is a linear relationship between height and volume in this example. With a constant radius value for this table, the volume is 4 times the size of the height of the cylinder.
Answer:
I think it may be B, but double check