Question

A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bottom where nothing is printed. What width should the poster be in order to have the largest printed area?

Answer 1

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } $cm^{2}$

This area is equal to 125 $cm^{2}$ as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ $a^{2}$ - 18 a +80 -125 =0

⇒ $a^{2}$ - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a $>$ 4.

Thus the required answer is 15 cm.

Answer 2

Answer:

15cm

Step-by-step explanation: