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Paladinen [302]
3 years ago
15

A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott

om where nothing is printed. What width should the poster be in order to have the largest printed area?
Mathematics
2 answers:
jeka57 [31]3 years ago
7 0

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } cm^{2}

This area is equal to 125 cm^{2} as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ a^{2} - 18 a +80 -125 =0

⇒ a^{2} - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a > 4.

Thus the required answer is 15 cm.

dmitriy555 [2]3 years ago
6 0

Answer:

15cm

Step-by-step explanation:

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Answer:

32.5 ft^2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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h=-0.004d^2+0.5d

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To solve this using a Ti-84, you can follow these steps (I'm using the Ti-84 Plus Silver Edition):

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2 years ago
BEG is a triangle. ABC and DEF are parallel lines. work out the size of angle x.
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Answer:

x=60^o

Step-by-step explanation:

The picture of the question in the attached figure

step 1

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we know that

m\angle BED+m\angle BEG+m\angle GEF=180^o ---->  by supplementary angles (form a linear pair)

substitute the given values

110^o+m\angle BEG+25^o=180^o

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step 2

Find the measure of angle HBC

we know that

m\angle HBC+m\angle ABH=180^o ---> by supplementary angles (form a linear pair)

we know that

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substitute the given values

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