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timofeeve [1]
2 years ago
7

Remove the brackets and simplify

Mathematics
2 answers:
Leto [7]2 years ago
8 0

Hey there!

5x - 7x^2 - (2x)^2

= 5x - 7x^2 - 4x^2

COMBINE the LIKE TERMS

(5x) + (-7x ^2 - 4x^2)

= -7x^2 - 4x^2 + (5x)

= -11x^2 + 5x

Therefore, your answer is: -11x^2 + 5

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Komok [63]2 years ago
7 0

Answer:

5x - 7 {x}^{2}  -  {(2x)}^{2}  \\  = ( {2}^{2}  {x}^{2} ) - 7 {x}^{2}  + 5x \\  = 4 {x}^{2}  - 7 {x}^{2}  + 5x \\  = x(4x - 7x + 5) \\  = x( 5 - 3x) \\  = { \underline{ \underline{ \:  \:  5x - 3 {x}^{2}  \:  \: }}}

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Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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