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3 years ago

9

Please help, this is so confusing: Which two-dimensional figure could be a cross section of a rectangular pyramid that has been

intersected by a plane perpendicular to its base and not through its vertex A a rectangle B A triangle C A hexagon D A trapezoid

1 answer:

satela [25.4K]3 years ago

4 0

The answer would be A) a rectangle<span>.</span>

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What transformation were applied to ABC to obtain A’B’C?

Cloud [144]

Answer:

A = (3,-2)

reflect along the y -axis ; set x=-x

(-3,-2)

reflect along the x-axis ; set y=-y

A' = (-3,2)

Same for B,C and D

ABCD is reflected across the y-axis and then the x-axis.

Step-by-step explanation:

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3 years ago

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Plzzzzz help <br><br><br> for brainliest<br> real answer or no brainliest

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Answer:

every 0.5 hours its 1.5 miles

Step-by-step explanation:

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3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

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4 years ago

The average amount that a college student spends on a textbook is $205 with a

zaharov [31]

Answer:

Step-by-step explanation:

Today's calculators have statistical functions built in.

A. Here we use:

normalcdf(10,310,205,35), WHICH returns 0.999.

B. normalcdf(135,275, 205,35) = 0.954

C. normalcdf(240, 10000, 205, 35) = 0.159

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3 years ago

A merry-go-round has a radius of 18 feet. If a passenger gets on a

sdas [7]

Answer:

121 degrees

Step-by-step explanation:

The "arc length" formula is s = rФ, where Ф represents the central angle in radians (not degrees).

Here r = 18 ft and s = 38 ft, and so:

38 ft

s = rФ becomes Ф = ------------ = 2.111 radians

18 ft

which, in degrees, is:

2.111 rad 180 deg

------------- * --------------- = 121 degrees, to the nearest degree

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3 years ago

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