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3 years ago

PLZ HELP!!

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

Pretty sure its A. Apartment A (mark brainliest if correct plz)

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Write the equation of the circle with center (3, 2) and with (9, 3) being a point on the circle. A) (x − 3)2 + (y − 2)2 = 13 Eli

Alexus [3.1K]

Answer:

D) (x - 3)^2 + (y - 2)^2 = 37

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2

We are given the center (3, 2), so we have h = 3, and k = 2.

The equation is now:

(x - 3)^2 + (y - 2)^2 = r^2

We need to find the radius.

The radius of a circle is the distance from the center of the circle to any point on the circle. We know the center, (3, 2), and we know a point on the circle, (9, 3). We can use the distance formula to find the distance between the center and that point which is the radius of the circle.

d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

d = sqrt[(9 - 3)^2 + (3 - 2)^1]

d = sqrt(6^2 + 1^2)

d = sqrt(37)

Now that we have the radius, we apply it to the equation of the circle.

(x - 3)^2 + (y - 2)^2 = (sqrt(37))^2

(x - 3)^2 + (y - 2)^2 = 37

Answer: D) (x - 3)^2 + (y - 2)^2 = 37

3 0

4 years ago

Suppose you have a cube of length s. The volume of that cube is V = s^3. Now let's suppose the dimensions of that cube (and henc

Grace [21]

Answer:

Part 1

s'(t)=1

$V'(t)=3t^2$

Part 2

$s'(t)=\frac{1}{3\sqrt[3]{t^2}}$

V'(t)=1

Step-by-step explanation:

As stated in the question, if s is the length of a cube, its volume is

$V(s)=s^3$

When s changes in time, the volume will change too. The challenge here is to find the growth of the volume in terms of those changes in length

Part 1

$s(t)=t$

The change of s with respect to time is found by differentiating the relation to get

$s'=1$

The volume will also change, and its derivative is

$V'(s)=3s^2.s'$

Since s'=1

$V'(s)=3s^2$

How s=t

$V'(t)=3t^2$

Part 2

$V(t)=t$

Replacing this into the formula for V(s)

$V(s)=s^3=t$

So we have

$s=\sqrt[3]{t}=t^{\frac{1}{3}}$

Computing the derivatives:

V(t)=t =>

V'(t)=1

$s'(t)=\frac{1}{3}t^{-\frac{2}{3}}=\frac{1}{3\sqrt[3]{t^2}}$

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3 years ago

In ABC, A and B have the same measure. The measure of C is twice the measure of A. Find the measures of the angles in triangles

stira [4]

Answer: A is 45 degrees, B is 45 degrees, C is 90 degrees.

Step-by-step explanation: A triangle is 180 degrees, and those three numbers add to that. This would be considered a right triangle due to the 90 degree angle.

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3 years ago

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The greatest whole number of square yards the teacher can buy is 4

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$8x + 10y \le 120$