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anastassius [24]
3 years ago
10

An experiment requires you to fill a test tube with hydrochloric acid. Find the bottle of acid and pour the contents into the te

st tube.
A. True

B. False
Chemistry
2 answers:
Maru [420]3 years ago
5 0

Answer: Option (A) is true.

Explanation:

In a laboratory, the solutions are prepared in advance so that as and when the need arises they can be easily available. As these solutions are prepared by keeping in mind the correct ratio of concentrations.

Hence, when a person need to fill a test tube with hydrochloric acid then he/she just need to find the bottle of acid and pour the contents into the test tube.

Thus, it can be conclude that the statement is true.

morpeh [17]3 years ago
5 0

Answer: True

Explanation:

In a laboratory if someone needs a test tube full of hydrochloric acid then it should be directly poured into the test tube.

As required in the experiment or during the experiment, the hydrochloric acid is pored and used in the experiment.

During the time of experiment the concentration of HCl can be adjusted base on the type of experiment.

So, it is true that hydrochloric acid can be poured directly in the test tube from the bottle.

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Tris base has a molecular weight of 121 g/mol. How many grams of tris base would you need to make 250ml of a 200mM SOLUTION
STatiana [176]

Answer:

6.05 g

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question ,

M = 200mM

Since,

1 mM = 10⁻³ M

M = 200 * 10⁻³ M

V = 250 mL

Since,

1 mL = 10⁻³ L

V = 250 * 10⁻³ L

The moles can be calculated , by using the above relation,

M = n / V  

Putting the respective values ,

200 * 10⁻³ M = n / 250 * 10⁻³ L

n = 0.05 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

m = 121 g/mol

n = 0.05 mol ( calculated above )

The mass of tri base can be calculated by using the above equation ,

n = w / m  

Putting the respective values ,

0.05 mol = w / 121 g/mol

w = 0.05 mol * 121 g/mol

w = 6.05 g

3 0
3 years ago
Read 2 more answers
2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Slav-nsk [51]

Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

0.589 moles of AgCl × (143.32g / mol) =<em> 84.4g of AgCl</em>

3 0
4 years ago
1. Lithium, water, edible salt, chalk, Carbon, Lime, Nitrogen, Potassium, Oxygen,
Kaylis [27]

Answer:

Explanation:

An atom is the smallest unit of an element that can take part in a chemical reaction. Atoms (and there corresponding symbols) mentioned in the question are

Lithium ⇒ Li

Carbon ⇒ C

Nitrogen ⇒ N

Potassium ⇒ K

Oxygen ⇒ O

Iron ⇒ Fe

Chlorine ⇒ Cl

A compound is substance that contains two or more atoms that are chemically combined and can be represented with a chemical formula. The compounds (and there corresponding formula) mentioned in the question are

Water ⇒ H₂O

Edible salt (sodium chloride) ⇒ NaCl

Chalk (calcium carbonate) ⇒ CaCO₃

Lime (calcium oxide) ⇒ CaO

Iodides (such as sodium iodide and potassium iodide) ⇒ NaI and KI respectively

8 0
3 years ago
How many grams are in .11 moles of Cu
kodGreya [7K]

Answer:

m= 6.9905 = 7 g

Explanation:

The formula is m= M.n

m= mass (g), M= Molar mass (g/mole), n= moles (moles)

Molar mass of Cu is 63.55

=) m= 63.55*0.11

   m= 6.9905 = 7 g

5 0
3 years ago
Which gas law can you use to solve for moles of gas
Sergio [31]

Answer:

it would be the ideal gas law also known as Avagadro's law

Explanation:

4 0
3 years ago
Read 2 more answers
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