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tatuchka [14]
3 years ago
14

How many moles are in 1.50 grams of ethanol, CH3CH2OH?

Chemistry
2 answers:
LekaFEV [45]3 years ago
4 0
CH3CH2OH = 46.068 (molar mass)
1.50g(1 mole / 46.0680) =
0.03256 moles
Galina-37 [17]3 years ago
4 0

<u>Answer:</u> The number of moles of ethanol for given amount is 0.0326 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of ethanol = 1.50 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{1.50g}{46.07g/mol}=0.0326mol

Hence, the number of moles of ethanol for given amount is 0.0326 moles.

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What is the volume of 8.7 * 10 ^ 23 molecules of chlorine gas (Cl 2 ) ?
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Answer:

32.3 dm³

Explanation:

Data given:

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For this formula used

    no. of moles = no. of molecules / Avogadros number

    no. of moles = 8.7 x 10²³ / 6.022 x 10²³

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for this formula used

                      no. of moles = volume of gas / molar volume

molar volume = 22.4 dm³/mol

Put values in above equation

                 1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol

rearrange the above equation

                 volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol

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