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tankabanditka [31]
3 years ago
5

Which expression are equivalent to q+p+p+q

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

p^2 + q^2 is the equivalent term

Step-by-step explanation:

Dimas [21]3 years ago
6 0

Answer:

I think it's iq

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Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury and the stan
liq [111]

Answer:

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 120, \sigma = 5.6

Find the probability that the individual's pressure will be between 119.4 and 121.4mmHg

This is the pvalue of Z when X = 121.4 subtracted by the pvalue of Z when X = 119.4. So

X = 121.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{121.4 - 120}{5.6}

Z = 0.25

Z = 0.25 has a pvalue of 0.5987

X = 119.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{119.4 - 120}{5.6}

Z = -0.11

Z = -0.11 has a pvalue of 0.4562

0.5987 - 0.4562 = 0.1425

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

8 0
3 years ago
What exponential function is the best fit for the data in the table?
gogolik [260]
Answer: fourth option

\frac{1}{4} 4^{x-1}-4

Explanation:

1) the pair x = 3 f(x) = 0, leads you to probe this:

f(3) = 0 = A [4 ^ (3 - 1) ] + C = 0

=> A [4^2] = - C

A[16] = - C

if A = 1/4

16 / 4 = 4 => C = - 4

That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4

2) Now you verify the images for that function for all the x-values of the table:

x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check

x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check

x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.

Therefore, you have proved that the answer is the fourth option.
6 0
3 years ago
Read 2 more answers
Which of these expressions can you simplify by combining like terms
Tom [10]

Answer:

top right bottom left

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
3 years ago
Factor 2x2 + 7x + 3. <br> (2x + 2)(x + 1) <br> (2x + 3)(x + 1) (2x + 1)(x + 3)
maks197457 [2]
<h3>Answer:</h3>

(2x + 1)(x + 3)

<h3>Step-by-step explanation:</h3>

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

_____

<em>Constructed solution</em>

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

Now, rewrite the x term using the sum of these numbers.

... 2x² +(1 +6)x +3

... 2x +x +6x +3 . . . . eliminate parentheses

... (2x +x) +(6x +3) . . . . group pairs of terms

... x(2x +1) +3(2x +1) . . . . factor each pair

... (x +3)(2x +1) . . . . . . matches the last selection

6 0
3 years ago
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