Answer:
Step-by-step explanation:
the vale of x differs in each situation are we talking AB value
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
Step-by-step explanation:
-18
Answer:
g(x) has a greater average rate of change
Step-by-step explanation:
From the given information, the table is:
<u>x | g(x)</u>
-1 7
0 5
1 7
2 13
From this table, we have g(0)=5 and g(2)=13
The average rate of change over [a,b] of g(x) is given by: 
This implies that on the [0,2]. the average rate of change is:
Also, we have that: f(0)=-4 and f(2)=-1.
This means that the average rate of change of f(x) on [0,2] is
Hence g(x) has a greater average rate of change on [0,2]
