Answer:
-a+-2b+4c
Step-by-step explanation:
Combine like terms
-4a+ 3a= -a
b+ -3b= -2b
3c+ c= 4c
The circumference of a circle is C=2πR, where R is the radius of the circle and π≈3.14.
So if we open the circumference of the circle into a straight line segment, the length of this segment is C=2πR≈2*3.14*R=6.28R
4 rotations mean 4 circumferences that is 4 segments of length 6.28R,
which makes a linear distance of 4*6.28R=25.12R
i: the radius of the smaller wheel is R=r, thus it covers a distance of 25.12r feet
ii: the radius of the smaller wheel is R=2r, thus it covers a distance of 25.12*2r=50.24r (feet)
50.24r is twice 25.12r, thus the larger wheel traveled Twice the distance of the smaller one.
Answer: the larger covered twice the distance of the smaller.
Answer:
n + 11 and 11 + n
Step-by-step explanation:
Let n be the unknown number,
n is increased by 11,
That is, n + 11
By the commutative property of addition,
The expression would be,
11 + n
For drawing a model that shows n + 11
Take two boxes in which first shows n and second shows 11 and add them,
Similarly, for showing 11 + n, take first box that shows 11 and second box that shows n then add them.
Answer: 1+1 = 2 :)
Step-by-step explanation:
6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
<u>Step-by-step explanation:</u>
We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:
Trenton's pet: 4/5 cup of dry food•
With 4/5 per day , for 14 days :
⇒ 
⇒ 
⇒ 
Maria's pet: 1.25 cups of dry food.
With 1.25 per day , for 14 days :
⇒ 
⇒ 
Subtracting Maria's - Trenton's :
⇒ 
That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks