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ddd [48]
3 years ago
7

A package of thumbtacks cost $0.80. What fraction on $1.00 does $0.80 represent?

Mathematics
1 answer:
Amanda [17]3 years ago
7 0

\frac{4}{5} represents the fraction on $1 does $0.80.

Answer: Option B

<u>Step-by-step explanation:</u>

A package of thumbtacks cost $0.80.Need to find out the fraction on $1.00 does $0.80 represent . Let the required fraction be ‘x’. So, according to question that,

              x=\frac{0.8}{1}=\frac{8}{10}=\frac{4}{5}

By multiply '10' on both denominator and numerator, we can cancel the decimal points in the above equation. So, \frac{4}{5} represents the fraction on $1 does $0.8.

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"Raju's father age is 5 years more than three times of Raju's age. Raju's father age is 50 years."​
Lana71 [14]

Let rajus age be x

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ATQ

\\ \bull\tt\longmapsto 3x+5=50

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Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38
Katyanochek1 [597]
To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the 

First, we will need to find the slope of this equation. To find this, we must simplify the equation 3x+5y=38 into y=mx+b form. Lets do it!

3x+5y=38
= 5y = -3x+38 (Subtract 3x from both sides)
= y= -\frac{3}{5}x+ \frac{38}{5} (Divide both sides by 5) 

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is \frac{5}{3}. 

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

\frac{y-y _{1} }{x- x_{1} }=m

Substituting values, we find that:

\frac{y-4}{x-6}= \frac{5}{3}

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that: 

y= \frac{5}{3}x-6 , which is our final answer.

Thank you, and I wish you luck.
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3 years ago
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Error error error error error
emmainna [20.7K]
Error error error error error error error

8 0
3 years ago
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