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Readme [11.4K]
4 years ago
5

A company makes chocolate candies in the shape of a solid sphere. Each piece of candy has a diameter of 6cm. If a box contains 2

0 pieces of candy, how much chocolate does the box contain?
Mathematics
2 answers:
ivolga24 [154]4 years ago
8 0

Answer:0.3


Step-by-step explanation:

Divide 6 by 20

Pachacha [2.7K]4 years ago
7 0

The Answer of this Question is 2.0 divide 6 divided by 20 = 2.0

Hope This Helps

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5.2.8. Suppose K1 and K2 are positive definite n × n matrices. Suppose that, for i = 1, 2, the minimizer of pi (x) = xTKix − 2xT
Svet_ta [14]

Answer:

Q7 if you multiplying matrix K1 and K2.The number of items on the row of K1 must be equal to the number of items on the columns of matrix K2 if not it's not applicable.

Step-by-step explanation:

7 0
3 years ago
Find the given radius or diameter of each circle with the given dimensions<br><br> R= 21 ft
Harlamova29_29 [7]

Answer:

D=2r thus: 42 ft

Step-by-step explanation:

6 0
3 years ago
The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re
musickatia [10]

Answer:

(a) P-value = 0.001

Conclusion: The average reflectometer reading for the new type of paint under consideration is greater than 20.

(b) P-value = 0.036

Conclusion: The average reflectometer reading for the new paint under consideration is 20

Step-by-step explanation:

The test is a one-tailed test because the alternate hypothesis is expressed using greater than.

(a) n = 16, t = 3.3, a = 0.05

Cumulative area of the test statistic t is 0.9995

P-value = 1 - 0.9995 = 0.0005 = 0.001 (to 3 decimal place)

Conclusion:

Reject H0 because the P-value 0.001 is less than the significance level 0.05.

(b) n = 8, t = 1.8, a = 0.01

Cumulative area of the test statistic t is 0.9641

P-value = 1 - 0.9641 = 0.0359 = 0.036 (to 3 decimal places)

Conclusion:

Fail to reject H0 because the P-value 0.036 is greater than the significance level 0.01

5 0
3 years ago
Write 44 as a product of prime factors.
Ann [662]

<u>Answer:</u>

  • Hence, 11 x 2 x 2 is the product of prime factors.

<u>Step-by-step explanation:</u>

<u>Let's divide by 2's.</u>

  • => 44 = 22 x 2
  • => 22 x 2 = 11 x 2 x 2

<em>Since 11 is a prime number, we cannot simplify it anymore. Hence, 11 x 2 x 2 is the product of prime factors.</em>

<em />BrainiacUser1357<em />

3 0
2 years ago
Please explain how to do #6 i know the work is right but i don’t understand it
mariarad [96]
Since this is part of a packet, there's a lot of prior knowledge you need to understand the question.
1) The angle of elevation is the angle between the horizontal and the light of sight from the object to the observer (see picture 1).

2) A lot of the units are from work done by an Indian astronomer. The line of sight (light blue in picture 1) is r = 3438 (I think you might have forgotten to finish writing the number). r, or 3438, is the distance from the earth to the sun used by Indian Astronomers. 

3) The table shows units in jya(θ<span>°). Jya is a Sanskrit (ancient Indian language) word. It stands for the length of half of a chord that connects two endpoints of a circle (kinda confusing and more information than you need to know - but it's the green line in picture 2).
What's important is: </span>jya(θ°) = r*sin(θ°)



Now let's tackle the problem:
1) You know that the angle of elevation is 67.5°. Using the chart, the only important value is the second from the bottom. jya(67.5°) = 3177. 

2) Remember that jya(θ°) = r*sin(θ°). 
Also remember that sine of an angle is \frac{opposite}{hypotenuse}. In this problem, r, the distance from the earth to the sun, happens to be the hypotenuse of the triangle since its the longest edge. 

3) Notice that you're dividing jya(θ°) (aka r*sin(θ°)) by r = 3438. That will give you sin(θ°) by itself. Then you're multiplying that sin(θ°) by 1 AU, which we are told is the actual distance of the hypotenuse/distance from earth to sun. Since sine = \frac{opposite}{hypotenuse} that gives you the apparent length of the opposite side = apparent height of the sun.

The math is a bit weird, but you're basically multiplying sine by the apparent distance 1AU to get the apparent height, instead of multiplying sine by the estimated height r = 3438. Dividing 3177 by 3438 gives you sin(67.5°). Then multiplying sin(67.5°) by the apparent hypotenuse, 1AU, gives you the apparent height. That's how I'm understanding it!

6 0
3 years ago
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