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Kobotan [32]
3 years ago
5

You can delete any content control by ____ it, and then clicking remove content control on the menu that opens.

Computers and Technology
1 answer:
Bezzdna [24]3 years ago
8 0
<span>You can delete any content control by Right Clicking it, and then clicking remove content control on the menu that opens.</span>
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Assume that the 100,000 element integer array that you allocated starts at address 0x50000000 in memory, the size of an integer
Vanyuwa [196]

Answer:

40, 5 and 3

See explaination for the details

Explanation:

A)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =4bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/4

= 160/4

= 40

b)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =32bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/32

= 160/32

= 5

c)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =64bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/64

= 160/64

= 3

6 0
3 years ago
Assume you are a manager in the security department of a high-tech corporation. You are mentoring Mary, an entry-level network t
nadya68 [22]

Answer:

Seek a bachelor's degree.

Explanation:

Seems more compromised and education from people with experience already.

6 0
3 years ago
Kristi, an event planner, wants to store caterers’ names and contact information in an organized manner. Kristi will MOST LIKELY
bixtya [17]

Answer:

Publisher Program

Explanation:

5 0
3 years ago
Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,
nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
  3. P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
  4. P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
  5. P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
  3. P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
  4. P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
  5. P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
  6. P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

  1. P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
  2. P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
  3. P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
  4. P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
  5. P5 will not be allocated to any of the available space because none can contain it.
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0
3 years ago
Lawanda starts a new job today at a company that delivers thousands of packages each day. Identify three ways in which Lawanda's
jek_recluse [69]

Answer:

use your own opinion

Explanation:

7 0
3 years ago
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