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iragen [17]
3 years ago
11

What is f(2) = 2x -6

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

f(2) = -2

Step-by-step explanation:

f(2) = 2x - 6

f(2) = 2(2) - 6

f(2) = 4 - 6

f(2) = -2

You might be interested in
Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
3 years ago
COLOR THEME
Lelu [443]

Answer:

the correct answer is A. Because it shows the equal qualifient of the answer

4 0
3 years ago
Whats the inverse of y=0.07x​
dmitriy555 [2]

Answer: y=0

Step-by-step explanation: i think this is right

3 0
3 years ago
How do you solve for x a=2x+6xz
maksim [4K]

a = 2x + 6xz

a = x(2 + 6z) <em>factored out "x" on right side</em>

a/(2 + 6z) = x <em>divided both sides by (2 + 6z)</em>

Answer: x = \frac{a}{2 + 6z}

8 0
3 years ago
702 001 in expanded form
OLga [1]
700,000+2,000+1, should be your answer.
3 0
3 years ago
Read 2 more answers
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