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-Dominant- [34]
4 years ago
15

Evaluate 2/3b-5a when a=-2 and b=3

Mathematics
1 answer:
den301095 [7]4 years ago
5 0
The answer is given above

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If three pies require 2 dozen apples, then four bird require ? dozen apples?
Nata [24]
Answer is 2-2/3 dozen apples, or 2.66 dozen as a repeating fraction.
Step by step
we know 2 dozen apples is 24 apples
We know 24 apples per 3 pies
To get the rate per pie, divide 24 apples per 3 pies
24/3 = 8 apples per pie
Now multiply 8 apples x 4 pies = 32 apples
Now we need to answer in how many dozen apples. Divide 32 by 12 (1 dozen)
Answer is 2.66 dozen apples or 2-2/3 dozen apples
3 0
2 years ago
PLease answer 1, 2, and 3 so I can be free till december
Kobotan [32]
Is there a picture for this?
3 0
3 years ago
A polygon is shown on a coordinate plane. The vertices are A at negative 6 comma 5, B at negative 6 comma 2, C at negative 2 com
GREYUIT [131]

Answer:

See below

Step-by-step explanation:

<u>Given a polygon with vertices</u>

  • A(-6, 5), B(-6, 2), C(-2, 2), D(-2, 6)

<u>Translation rule is</u>

  • T(5, -4)

<u>New coordinates are</u>

  • A' = (-6 + 5, 5 - 4) = (-1, 1)
  • B' = (-6 + 5, 2 - 4) = (-1, -2)
  • C' = (-2 + 5, 2 - 4) = (3, -2)
  • D' = (-2 + 5, 6 - 4) = (3, 2)

8 0
3 years ago
For each graph, calculate the slope of the line.<br> Whew is the slope between 2,6 and 8,4
Tom [10]

Answer:

-1/3

Step-by-step explanation:

First, slope is change in y over change in x, or rise over run. Plugging these points in, (y2-y1)/(x2-x1)=(6-4)/(2-8), or 2/-6, simplifying, the slope= -1/3.

4 0
3 years ago
Read 2 more answers
Verify the following identity. <br><br> <img src="https://tex.z-dn.net/?f=-%5Cfrac%7Bcos%283x%29%2Bcos%285x%29%7D%7Bsin%283x%29-
kogti [31]

Recall the angle sum identities:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

sin(a + b) = sin(a) cos(b) + sin(b) cos(a)

sin(a - b) = sin(a) cos(b) - sin(b) cos(a)

Notice that adding the first two together, and subtract the last from the third, we get two more identities:

cos(a + b) + cos(a - b) = 2 cos(a) cos(b)

sin(a + b) + sin(a - b) = 2 sin(b) cos(a)

Let a = 4x and b = x. Then

cos(5x) + cos(3x) = 2 cos(4x) cos(x)

sin(5x) - sin(3x) = 2 sin(x) cos(4x)

Now,

-\dfrac{\cos(3x)+\cos(5x)}{\sin(3x)-\sin(5x)}=\dfrac{\cos(5x)+\cos(3x)}{\sin(5x)-\sin(3x)}=\dfrac{2\cos(4x)\cos x}{2\sin x\cos(4x)}=\dfrac{\cos x}{\sin x}=\cot x

as required.

4 0
4 years ago
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