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8090 [49]
3 years ago
5

How do you write the equation in point slope form given slope=8, passing through (4,-1)?

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0

Point slope form, y-y1 = m(x-x1)

Here, y1 = -1, x1 = 4, m=8

so, it would be: (y+1) = 8(x-4)

zlopas [31]3 years ago
7 0
Point slope for slope m and point (x1,y1) is Y-y1=m(x-x1) Slope given is8 and point is (4,-1) y+1=8(x-4)
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4/7 of what number is 28
kozerog [31]

Answer:

44

Step-by-step explanation:

7 0
3 years ago
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Write the equation of a line that is parallel to the following:<br><br> 1. x = 5<br><br> 2. y = -3
sineoko [7]

Answer:

1.  x=6

2.  y=2

Step-by-step explanation:

If x=5, the line is vertical, so we need a vertical line so that we are parallel.  A vertical line is x= a constant

We can choose the value for x as long as it is not 5, that would make it the same line.  I will choose x=6

If y=-3=5, the line is horizontal, so we need a horizontal line so that we are parallel.  A horizontal line is y= constant

We can choose the value for y as long as it is not -3, that would make it the same line.  I will choose y=2

3 0
3 years ago
What is the equation of a parabola with a directrix x = 8 and focus (-8,0)
andrew11 [14]
From the given information, the parabola is a sideways parabola facing left with vertex at the origin.
Required equation is (y - 0)^2 = 4p(x - 0)
y^2 = 4px

But 0 + p = -8 => p = -8

Therefore, required equation is y^2 = 4(-8)x
y^2 = -32x
7 0
3 years ago
Is x-2 a factor of 4x^5 +5x^4 +1?
nordsb [41]

Answer:

No

Step-by-step explanation:

By the Factor theorem

If (x - h) is a factor of f(x) then f(h) = 0

Here (x - 2) with h = 2 and f(x) = 4x^{5} + 5x^{4} + 1 , then

f(2) = 4(2)^{5} + 5(2)^{4} + 1

     = 4(32) + 5(16) + 1

     = 128 + 80 + 1

     = 209

Since f(2) ≠ 0 then ( x - 2) is not a factor

 

8 0
3 years ago
What is (d^1 3^1 d^3)^2
stepan [7]

Answer:

Simplify the solution: 13^1d^3

Step-by-step explanation:

Any expression raised to the power of one equal itself.

3 0
3 years ago
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