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Digiron [165]
3 years ago
15

A carriage on a carnival ride can hold up to 4 people. How many carriages are needed for a group of 22 people to ride?

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

Hello!

Let's simply divide our two numbers to find how many carriages we need.

22/4=5.5

The thing is, we cannot have 5.5 carriages. We can just have an extra carriage with only 2 people. This gives us 6 carriages.

Therefore, our answer is 6.

I hope this helps!

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Please help, will mark Brainly and if you need help with anything I’ll help with any work you send
inessss [21]

Answer:

The first one is missing (d - 9) so it would be 5(d -9) or when you factor it out 5d - 45

In the second one (d + 7) is missing so it will be 8d(d + 7) so if you factor that out you will receive 8d^2 + 56

Step-by-step explanation:

3d^2 + 18d -21 =(3d -3)( d + 7)

3d^2 -30d +27 =(3d -3)(d - 9)

6 0
3 years ago
What is the rate of change?
Sergio [31]

Answer:5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The product of 3 consecutive odd numbers is 2,145. Enter a simplified expression for finding the numbers. Let n be the first odd
Arlecino [84]

Answer:

11, 13 and 15.

Step-by-step explanation:

Let's say that the odd number is "x". If x is for example 15, then the next ODD number would be 15+2=17 and the one after that would be 15+2+2=15+4=19.

Applying that here, we get:

Odd number* the next odd number*the next odd number=2145

x*(x+2)*(x+4)=2145

x*(x^2+4x+2x+8)=2145

x^3+6x^2+8x=2145

By solving the polynomial, you get x=11.

Which makes our three numbers: 11, 13 and 15.

11*13*15=2145. The answer checks.

6 0
4 years ago
1.what is a sports car average acceleration if it can go from 0m/s to 27m/s in 6.0 seconds?
Flauer [41]

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

t

27-0

------ = 27/6

6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

5 0
2 years ago
HELP
KiRa [710]
M=2,000÷((1−(1+0.072÷12)^(−12
×2))÷(0.072÷12))
M=89.73
8 0
3 years ago
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