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2 years ago

Can someone please help me (6th grade math) please and thank you!

Mathematics

1 answer:

Assoli18 [71]2 years ago

7 0

Answer and Step-by-step explanation:

First, you create an expression that equals the perimeter of the shape.

5r + 2s + 3r + 2s + 5r + 2s + 3r + 2s

Simplify

16r + 8s

Now we look at the students' expressions.

I can see that Brain's expression is equivalent to perimeter of the shape. Do you know why?

It is because his answer is the un-distributive version of our answer.

He simply took out the common number that is in 16 and 8, which 8.

So, Brian is correct.

#teamtrees #PAW (Plant And Water)

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Shelley ran 20 minutes and burned 130 calories. How many calories did Shelly burn per minute?

Savatey [412]

ANSWER

6.5 calories per minute.

EXPLANATION

To find the calories Shelley burned per minute, divide the total calories burned by the total minutes ran.

Calories burned for a minute

$= \frac{130}{20}$

This will give us,

$= \frac{13}{2}$

$= 6.5 \: calories$

3 0

3 years ago

Steve travels 5 times as fast as Kevin. Traveling in opposite directions, they are 390 miles apart after 5 hours. Find their rat

Kaylis [27]

Answer:

steve=65 mph

kevin=13 mph

Step-by-step explanation:

steve=s

kevin=k

s=5

k=1

1=5=6

390 divided by 6 equals s 65

divide further by 5 which equals k 13

3 0

2 years ago

When 80% of a number is added to the number, the result is 252. what is the number

Rashid [163]

I Think The Answer Is 140.

The Expression: 0.8x + x = 252 Can Explain The Answer If x = 140.
Or: 1.8 Times x = 252 If x = 140.

3 0

2 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

HELP ME PLEASE I NEED THIS <3333

WITCHER [35]

Answer:

214°

Step-by-step explanation:

The arc subtending an angle at the centre are equal, that is

arc ED = 90° and

arc DF = 360° - (90 + 146)° = 360° - 236° = 124°

Thus

arc EDF = arc ED + arc DF = 90° + 124° = 214°

4 0

3 years ago