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4 years ago

What is 0.09 times 64?

Mathematics

2 answers:

erma4kov [3.2K]4 years ago

8 0

Answer: 5.76

Step-by-step explanation:

0.09 x 64 implies 0.09 in 64 places

To solve this, Multiply 0.09 x 64

It gives 5.76

Ierofanga [76]4 years ago

5 0

Answer:

5.76

Step-by-step explanation:

0.09 times 64 equals 5.76

To make this equation easier to solve, it could help to set the equation up like this:

0.09

x 64

---------

Then just multiply (don't forget your decimal!)

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raketka [301]

Answer:

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3 years ago

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago

Show work please thanks

Tju [1.3M]

Be more specific on the first one

3 0

3 years ago

Nina makes $12 per hour at her job. She also earns commission. Last week she earned $78 in commission and made a total of $444.

Vesnalui [34]

Answer:

30.5 hours

Step-by-step explanation:

444-78=366

366/12=30.5

30.5 x 12= 366

7 0

3 years ago

Read 2 more answers

Y is directly proportional to the square of x.

RUDIKE [14]

Answer:

The value of y is 847 for x=11

Step-by-step explanation:

It is given that y is directly proportional to the square of x

This can be written mathematically as:

$y \propto x^2$

Removing the proportionality symbol introduces a proportionality constant in the equation which is denoted by k

$y = kx^2$

Given that "When x is 5, y is 175"

$175 = k (5)^2\\175 = k*25\\k = \frac{175}{25}\\k = 7$

Putting the value of k

$y = 7x^2$

Now putting x = 11

$y = 7(11)^2\\y = 7 * 121\\y = 847$

Hence,

The value of y is 847 for x=11

5 0

3 years ago