Percentage of part time employees = (part-time employees/total employees) * 100 = (6/60) * 100 = 1/10 * 100 = 10%
Answer:
not really what unit test or topic is that ?
Answer:
We have 197 g of Co-60 after 18 months.
Step-by-step explanation:
We can use the decay equation.

Where:
- M(f) and M(i) are the final and initial mass respectively
- λ is the decay constant (ln(2)/t(1/2))
- t(1/2) is the half-life of Co
- t is the time at the final amount of m
<u>Therefore, we have 197 g of Co-60 after 18 months.</u>
I hope it helps you!
Answer:
Step-by-step explanation:
731² - 631² is the difference of squares.
731² - 631² = (731+631)(731-631) = 1362×100
therefore, 731² - 631² is divisible by 100
The expression of the problem is, 8x.
where "x" stands for the number of dogs. so you would then substitute x with 12. Then you would solve the problem to get your answer.(8•12)