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Alborosie
3 years ago
10

Can someone explain how to do these? You can just pick one of them...ignore my incorrect answers

Mathematics
2 answers:
bearhunter [10]3 years ago
5 0
You did it correctly
BlackZzzverrR [31]3 years ago
4 0
3)x=m-z 4)correct
5)x=k+u 6)x=-c+g
7)a=k/u 8)x=cg
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What is the solution to this equation?<br> 2x + 3 = x – 4
gavmur [86]

Answer:

<h3>x = -7</h3>

Step-by-step explanation:

2x + 3 = x – 4

2x - x = -3 - 4

x = -7

5 0
2 years ago
Norman makes $15 commission for selling $200 in merchandise. he makes $37.50 commission for selling $500 in merchandise. assumin
vladimir2022 [97]

So he needs to sell $2,000 in merchandise.

<h3>what is the total value of merchandise he needs to sell?</h3>

We can assume that we have a proportional relation:

y = k*x

Where y is the commission and x is what Norman sells, then:

$15 = k*$200

k = $200/$15 = 0.075

$37.50 = k*$500

k = $500/$37.50 = 0.075

Then the relation is:

y = 0.075*x

If he wants a commission of $150, then:

$150 = 0.075*x

$150/0.075 = x = $2,000

So he needs to sell $2,000 in merchandise.

If you want to learn more about proportional relationships:

brainly.com/question/12242745

#SPJ1

3 0
2 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
2 years ago
What’s 3.8 - (-7.45)
Varvara68 [4.7K]

it is 11.25................................

6 0
3 years ago
Please help! What is 75 ÷ 12.5 ?<br><br> ( WILL MARK BRAINLIEST )
shtirl [24]
The answer to 75 ÷12.5 is 6
7 0
3 years ago
Read 2 more answers
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