EQ. 1: x + y = 8
EQ. 2: 4x-y = 7
Rewrite EQ. 1 as EQ. 3: x = 8-y
Replace x in EQ.2 with EQ. 3:
4(8-y) - y = 7
Use the distributive property:
32 - 4y - y = 7
Combine like terms:
32 - 5y = 7
Subtract 32 from each side:
-5y = -25
Divide both sides by -5
y = -25 / -5
y = 5
Now replace y with 5 in EQ. 3 to solve for X:
x = 8-5
x = 3
The point of intersection is X = 3, Y = 5, which is written as (3,5)
There are 6 pockets all together. You checked two of them and it wasn't
there. So you can forget about those 2, and now there are 4 pockets left.
The total number of ways for your next try is 4.
The number that will be successful is 1.
The probability of success on the next one is <em>1/4 = 25% .</em>
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Another method of solution, somewhat more complex:
Total number of pockets = 6.
Amount of money missing = $10
First partial sum, i.e. sum of numbers
in the first part of the problem = 6 + 10 = 16.
Total number of pockets = 6
Current value of cargo pants on a fashion scale from 1 to 10 = -2.
Second partial sum = 6 - 2 = 4.
Probability = (second partial sum) / (first partial sum) = 4/16 = <em>25% </em>.
Sorry need points don't know the question
Answer:
4 I guess
Step-by-step explanation:
Because
3-1=2
2^2=2*2=4
