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Paladinen [302]
3 years ago
14

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

rticipant at random, what is the probability they play basketbali? b) If we pick 2 athletes at random (without replacement), what is the probability we get one volleyball player and one basketball player?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

A) \dfrac{11}{23}

B) \dfrac{88}{345}

Step-by-step explanation:

A survey of 46 college athletes found that

  • 24 played volleyball,
  • 22 played basketball.

A) If we pick one athlete survey participant at random,  the probability they play basketball is

P_1=\dfrac{22}{46}=\dfrac{11}{23}

B) If we pick 2 athletes at random (without replacement),

  • the probability we get one volleyball player is \dfrac{24}{46}=\dfrac{12}{23};
  • the probability we get another basketball player is \dfrac{22}{45} (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}

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The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.

<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>

To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:

We need to find 37% of 55 as shown below:

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So after 2 days I will have 75.35 microorganisms.

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On the fourth day I will have: 103.22 microorganisms.

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On the sixth day I will have 141.41 microorganisms.

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On the tenth day I will have 245.41 microoganisms.

Learn more about percentages in: brainly.com/question/13450942

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

<u>Step 1: Define expression</u>

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<u>Step 2: FOIL</u>

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