Let n be the man's walking rate. Then:
9/n+9/27=3&1/3
243+9n=90n
243=81n
n=3
The man's walking rate was 3 mph
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Answer:
is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.
Step-by-step explanation:
Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.
First term of given arithmetic progression is A
and common difference is D
ie.,
and common difference=D
The nth term can be written as

pth term of given arithmetic progression is a

qth term of given arithmetic progression is b
and
rth term of given arithmetic progression is c

We have to prove that

Now to prove LHS=RHS
Now take LHS




![=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5BAq%2BpqD-Dq-Ar-prD%2BrD%5D%5Ctimes%20qr%2B%5BAr%2BrqD-Dr-Ap-pqD%2BpD%5D%5Ctimes%20pr%2B%5BAp%2BprD-Dp-Aq-qrD%2BqD%5D%5Ctimes%20pq%7D%7Bpqr%7D)




ie., 
Therefore
ie.,
Hence proved
Answer:
256
Step-by-step explanation:
16 ×16= 256
Hope it works out for you
Given a = 3 and b = - 8 ,
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152