A television camera is positioned 4000 ft from the base of a rocket launching pad. The angle of elevation of the camera has to c
hange at the correct rate in order to keep the rocket in sight. Also, the mechanism for focusing the camera has to take into account the increasing distance from the camera to the rising rocket. Let’s assume the rocket rises vertically and its speed is 600 ft/s when it has risen 3000 ft.
(a) How fast is the distance from the television camera to the rocket changing at that moment?
(b) If the television camera is always kept aimed at the rocket, how fast is the camera’s angle of elevation changing at that same moment?
(a) How fast is the distance from the television camera to the rocket changing at that moment?
(b) If the television camera is always kept aimed at the rocket, how fast is the camera’s angle of elevation changing at that same moment?
1 answer:
Answer:
a) the time speed for distance from the television camera to the rocket is changing at rate of 360 ft/sec
b) camera’s angle of elevation changing at the rate of 0.096 radians/ sec
Step-by-step explanation:
details and step by step explanation is in the images below
image I is for Solution of a)
image 2 is for Solution of b)
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Answer:
2 and 5
Step-by-step explanation:
The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.
The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.
The standard form a line is ax+by=c.
So anyways parallel lines have the same slope.
So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.
3x-4y=7
Goal: Put into slope-intercept form
3x-4y=7
Subtract 3x on both sides:
-4y=-3x+7
Divide both sides by -4:
Simplify:
So the slope of this line is 3/4. So our line that is parallel to this one will have this same slope.
So we know our line should be in the form of .
To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).
So plugging this in to solve for b now:
so the equation of our line in slope-intercept form is
So that isn't option 1 because the slope is different. That was the only option that was in slope-intercept form.
The standard form of a line is ax+by=c and we have 2 options that look like that.
So let's rearrange the line that we just found into that form.
Clear the fractions because we only want integer coefficients by multiplying both sides by 4.
This gives us:
Subtract 3x on both sides:
I don't see this option either.
Multiply both sides by -1:
I do see this as a option. So far the only option that works is 2.
Let's look at point slope form now.
We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).
y-y1=m(x-x1)
Plug in like so:
y-(-2)=3/4(x-(-4))
y+2=3/4 (x+4)
So option 5 looks good too.
Answer: If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.
Step-by-step explanation:
Let x = Number of weeks.
As per given question ,
Weight of Frank after x weeks = 160+2x (pounds)
Weight of John after x weeks = 208-3x (pounds)
When Weight of Frank= Weight of John
Weight of Frank after 9.6 weeks = 160+2(9.6) = 179.2 pounds
Weight of John after 9.6 weeks = 208-3(9.6)=179.2 pounds
Hence, If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.