A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².
Answer:
x=-13/2
Step-by-step explanation:
13 3/4=55/4
7 1/4=29/4
---------------------
55/4+x=29/4
x=29/4-55/4
x=-26/4
simplify
x=-13/2
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Tricky but not crazy hard. You could use th x/y method where you turn it into a cross multiplication fiasco.
or you can try your guesses through what ever equals 1/2 when you add one to the denominator. the answer you are looking for is 2/3
2/3 + 1 for the numerator = 1.
2/3 + 1 for the denominator = 1/2.
The unit rate would be 11/2. Hope this helped.
