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Harrizon [31]
3 years ago
15

The formula for the area of a rectangle is A = l ∙ w, where A = area, l = length and w = width. The area of a rectangle with a l

ength of 12 inches and width of 5 inches is square inches.
Mathematics
1 answer:
padilas [110]3 years ago
6 0

Answer:

60 square inches

Step-by-step explanation:

Area = length x width

L = 12 inches

W = 5 inches

Area = 12 x 5

= 60 square inches

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IRISSAK [1]

Answer:

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Step-by-step explanation:

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3 years ago
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List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct
zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

\sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{\alpha /2}^{}}}

s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }

Where:

\bar x = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

\bar x = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} } = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }

\sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{0.872}}

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0
3 years ago
7y+65.7=2 true or false(don't answer that I just don't want this taken down(unless you do actually have the answer) is anyone in
Sophie [7]

It's false and same lol

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AURORKA [14]
You answered would be n is greater or equal to 4 but u have to us that symbol
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Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,ax
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ok this is answer any questions

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