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kumpel [21]
4 years ago
9

Admission for a water park is $17.50 per day. A season pass costs $125. A locker rental costs $3.50 per day. What is an equation

that represents the relationship between the cost of a daily pass and cost of a season pass?
Mathematics
2 answers:
ch4aika [34]4 years ago
8 0
Daily __ 17.50d + 3.50d=C
Seasonal __ 125+3.50d=C

D= the number of days they went and C =the total cost of the trip
HACTEHA [7]4 years ago
4 0

Answer:

y=21*x

Step-by-step explanation:

The cost of $17.50 is need per day and a locker rental costs $3.50 per day as $125 is needed for a season pass.

Let x equal the number of days and y equal the total amount needed for a season pass. We can write an equation relating the daily cost to and the season pas s and we assume you must rent a locker everytime you pay for a daily pass while it is included in the price for a season pass.

y=17.50*x+3.50*x

y=21*x

The number of daily pass relation to the season pass can determine if you should pay a day pass or a season pass based on the number of days.

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Answers:

x = 6 and P = 128

=================================================================

Explanation:

The tangents CT and CU are equal to each other. The rule is that tangent segments that meet at a common point are the same length.

Let's solve for x

CT = CU

3x = 18

x = 18/3

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Because CT = 18, this makes BC = BT+TC = 12+18 = 30

---------------------------

For similar reasoning as mentioned earlier, we can say tangents BT and BV are the same length. This means BV = 12.

Segment CD = 52 and CU = 18, which makes UD = CD-CU = 52-18 = 34

From there, we can say segment DV = 34 also. This leads to BD = BV+VD = 12+34 = 46

Triangle BCD has the three sides

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The perimeter is

P = sum of the three sides

P = (side1)+(side2)+(side3)

P = BC + CD + BD

P = 30+52+46

P = 82+46

P = 128

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3 years ago
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nadya68 [22]
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Now we are at \frac{24+ \sqrt{35} }{2} Which is the lowest possible simplified version while remaining at exact value. 

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