The value of x is ?

pishuonlain [190]

2x2 [4x 3x]
[12x 8x] I found the answer on the app math papa.

3 0

3 years ago

A series if license plates are being produced that all have the same pattern of three letters (a-z) followed by three digits (0-

Goshia [24]

If no letters or numbers are repeated, then the number of possibilities will be 11,232,000. Then the probability that the license plate is ABC123 or MOM678 will be 1/8,788,000.

<h3>What are permutation and combination?</h3>

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

A series of license plates are being produced that all have the same pattern of three letters (a-z) followed by three digits (0-9) without any repeats.

If no letters or numbers are repeated, then the number of the possibilities will be

Number of ways = 26 × 25 × 24 × 10 × 9 × 8

Number of ways = 11,232,000

Then the probability that the license plate is ABC123 or MOM678 will be

$P = \dfrac{1}{17,576,000}+\dfrac{1}{17,576,000}\\\\P = \dfrac{1}{8,788,000}$

More about the permutation and the combination link is given below.

brainly.com/question/11732255

#SPJ1

5 0

2 years ago

The distance between flaws on a long cable is exponentially distributed with mean 12 m.

Elden [556K]

Answer:

(a) The probability that the distance between two flaws is greater than 15 m is 0.2865.

(b) The probability that the distance between two flaws is between 8 and 20 m is 0.3246.

(c) The median is 8.322.

(d) The standard deviation is 12.

(e) The 65th percentile of the distances is 12.61 m.

Step-by-step explanation:

The random variable X can be defined as the distance between flaws on a long cable.

The random variable X is exponentially distributed with mean, μ = 12 m.

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{12}=0.0833$

The probability density function of X is:

$f_{X}(x)=0.0833e^{-0.0833x};\ x\geq 0$

(a)

Compute the probability that the distance between two flaws is greater than 15 m as follows:

$P(X\geq15)=\int\limits^{\infty}_{15}{0.0833e^{-0.0833x}}\, dx\\=0.0833\times \int\limits^{\infty}_{15}{e^{-0.0833x}}\, dx\\=0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{\infty}_{15}\\=e^{0.0833\times 15}\\=0.2865$

Thus, the probability that the distance between two flaws is greater than 15 m is 0.2865.

(b)

Compute the probability that the distance between two flaws is between 8 and 20 m as follows:

$P(8\leq X\leq20)=\int\limits^{20}_{8}{0.0833e^{-0.0833x}}\, dx\\=0.0833\times \int\limits^{20}_{8}{e^{-0.0833x}}\, dx\\=0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{20}_{8}\\=e^{0.0833\times 8}-e^{0.0833\times 20}\\=0.51355-0.1890\\=0.32455\\\approx0.3246$

Thus, the probability that the distance between two flaws is between 8 and 20 m is 0.3246.

(c)

The median of an Exponential distribution is given by:

$Median=\frac{\ln (2)}{\lambda}$

Compute the median as follows:

$Median=\frac{\ln (2)}{\lambda}$

$=\farc{0.69315}{0.08333}\\=8.322$

Thus, the median is 8.322.

(d)

The standard deviation of an Exponential distribution is given by:

$\sigma=\sqrt{\frac{1}{\lambda^{2}}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{\frac{1}{\lambda^{2}}}$

$=\sqrt{\frac{1}{0.0833^{2}}}\\=12.0048\\\approx 12$

Thus, the standard deviation is 12.

(e)

Let x be 65th percentile of the distances.

Then, P (X < x) = 0.65.

Compute the value of x as follows:

$\int\limits^{x}_{0}{0.0833e^{-0.0833x}}\, dx=0.65\\0.0833\times \int\limits^{x}_{0}{e^{-0.0833x}}\, dx=0.65\\0.0833\times |\frac{e^{-0.0833x}}{-0.0833}|^{x}_{0}=0.65\\-e^{-0.0833x}+1=0.65\\-e^{-0.0833x}=-0.35\\-0.0833x=-1.05\\x=12.61$

Thus, the 65th percentile of the distances is 12.61 m.

4 0

3 years ago

Can someone please tell me what the area of this thing is?

g100num [7]

Area of small triangle = 1/2bh = 1/2(5)(2) = 5
area of large triangle = 1/2bh = 1/2(6)(4) = 12
area of trapezoid = 1/2(b1+b2)h = 1/2(11+14)(2) = 25

area of figure = 5 + 12 + 25 = 42

7 0

4 years ago

Can some one help me with Dilation rule plz

inna [77]

Answer:

B. (x, y) --> (7/2x, 7/2y)

Step-by-step explanation:

I can't tell for sure, so I am assuming the large circle is the image, Circle C', and the small circle is the original circle C.

The radius of circle C is 2 units.

The radius of circle C' is 7 units.

To find the scale of the dilation divide the new size by the old size.

New size: 7 units

Old size: 2 units

scale: 7/2

The scale of the dilation is 7/2.

Answer: B. (x, y) --> (7/2x, 7/2y)

8 0

3 years ago