Answer:
a. autotriploid of species A: 63 chromosomes
b. autotetraploid of species B: 96 chromosomes
c. allotriploid from species A and B: 1) 66 chromosomes and 2) 69 chromosomes
Explanation:
<u>For a.</u>
this species will have 3 haploid sets of chromosomes ('tri' means 3)
one haploid set = 21
21 × 3 = 63 chromosomes
<u>For b.</u>
this species will have 4 haploid sets of chromosomes ('tetra' means 4)
one haploid set = 24
24 × 4 = 96 chromosomes
<u>For c.</u>
there are two ways to do this:
1) two sets of chromosomes from species A and one from species B
42 + 24 = 66 chromosomes
2) one set of chromosomes from species A and two from species B
21 + 48 = 69 chromosomes
Hope that answers the question, have a great day!
E. 0%
X-linked dominant disorders are not very common in females because it has to be on BOTH of their alleles in order to occur phenotypically.
Because you get one chromosome from your mom and another one from your dad, it would be impossible for the daughter to get the disorder because the dad doesn’t have it on his X chromosome to pass on to her.
In the case of the daughter, the focus is whether or not the dad has the disorder, the mom isn’t as relevant. However, if you were talking about a son, it would be a different story.
Hope this helps :)
Answer: Strict Liability Torts
Explanation:
In the tort law, strict liability is the imposition of the liabilities on the party without even finding a single fault.
The claimant only needs to prove that the tort occurred is done by the defendant and he is only responsible for the faults.
It is considered to be very dangerous as there is no need of prove to show the defendant has done a fault.
Pea plants have 2 different variations for their genes. Ex: All of the offspring get Y for yellow plant and y for the green plant so they are all Yy. Yy is a yellow plant. yy is a green plant because of gene variations
