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4 years ago

14

393 is three times as much as some number?

1 answer:

never [62]4 years ago

8 0

393 is 3 times as much as 131 because 393/3 is 131 and 131 times 3 is 393

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Sally is paid a fixed amount of money to walk her neighbor’s dog every day after school. When she is paid each month, she puts a

Ne4ueva [31]

Answer:

118.625

Step-by-step explanation:

Lets clear this up.

M = $65.

6 months = 182.5 days

We may turn 65 into a decimal for a more exact answer.

<h3>65 = 0.65 (changing it to a decimal does not change the value.)</h3>

Now we can do

182.5 x 0.65

= 118.625.

For your homework you could say.

"6 months is 182.5 days, we would need to change 65 into a decimal, which is 0.65 to get a more exact answer. 182.5 x 0.65 = 118.625. Sally will be paid 118.625 in 6 months."

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3 years ago

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What is the sum? -3+(-11)

Natasha_Volkova [10]

-3 + (-11) = -14 is the answer

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3 years ago

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(Algebra II) The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangl

qwelly [4]

A) 22.5 cm, 30 cm, and 37.5 cm

Divide 90 by 12 and multiply by three to check if any triplet has the answer in it. In this case only A

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4 years ago

A rectangular prism is 2 meters long, 50 centimeters wide, and 1 meter high. What is its volume? (Hint: How many centimeters are

Virty [35]

Volume
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V = 100 cubic centimeters

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4 years ago

Pls help asap, I put attachments down below, I will also give brainliest

lesya [120]

Answer:

Question 1;

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

∴ The y values are -9 , -3 , 3 and 9

Question 4;

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

Step-by-step explanation:

Question 1;

Given data,

Apples cost $\$1.49$ per pound.

$x$ = weight in pound

$y$ = Cost in $\$$

Here the relation between $x$ and $y$ comes;

$y=x\times 1.49$ (equation 1)

Let, Plug all x value in equation 1;

when $x=1$ then $y=1\times 1.49=1.49$ ,

when $x=2$ then $y=2\times 1.49=2.98$ ,

when $x=3$ then $y=3\times 1.49=4.47$ ,

when $x=4$ then $y=4\times 1.49=5.96$ ,

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

From question,

Initial fees of cab is $\$$ 2.00 and Passengers are charged $\$$ 0.80 for every minute.

Let,

$x$ = Time in minutes

$y$ = Amount in $\$$

Here the relation between x and y comes;

$y=x\times 0.80 +2.00$ (equation 2)

Let,By plug all x value in equation 2;

When $x=0$ then $y=0\times 0.80+2.00=2.00$ ,

When $x=1$ then $y=1\times 0.80+2.00=2.8$ ,

When $x=2$ then $y=2\times 0.80+2.00=3.6$ ,

When $x=3$ then $y=3\times 0.80+2.00=4.4$ ,

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

Given relation between $x$ and $y$ ;

$y=6\times x +3$

Plug all the values of x in above equation,

When $x=-2$ then $y=(6\times -2) +3=-9$ ,

When $x=-1$ then $y=(6\times --1) +3=-3$ ,

When $x=0$ then $y=(6\times 0) +3=3$ ,

When $x=1$ then $y=(6\times 1) +3=9$ ,

∴ The y values are -9 , -3 , 3 and 9

Question 4;

Given relation between $x$ and $y$ ;

$y=(\frac{1}{4} \times x)+1$

Plug all the values of x in above equation,

When $x=-2$ then $y=(\frac{1}{4} \times -2)+1=\frac{1}{2}$ ,

When $x=-1$ then $y=(\frac{1}{4} \times -1)+1=\frac{3}{4}$ ,

When $x=0$ then $y=(\frac{1}{4} \times 0)+1=1$ ,

When $x=1$ then $y=(\frac{1}{4} \times 1)+1=\frac{5}{4}$ ,

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

7 0

4 years ago