Answer:
x
=
6
,
−
5
Step-by-step explanation:
Move x
to the left side of the equation by subtracting it from both sides. x^
2
−
30
−
x
=
0
x2-30-x=0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)/
2
a
-b±b2-4(ac)/2a
Substitute the values
a
=
1 , b
=
−
1 , and c
=
−
30
into the quadratic formula and solve for x
x
.
1
±
√
(
−
1
)
2
−
4
⋅
(
1
⋅
−
30
)/
2
⋅
1
Simplify.
x
=
1
±
11/
2
The final answer is the combination of both solutions.
x
=
6
,
−
5
Multiplying both sides of the equation by 3 and substituting 4 for p
Ok so remember
x^n means x times itself n times
example
x^2=x times x
x^4=x times x times x times x
so
a^3
a=7
a^3=a times itself 3 times therefor
a^3=a times a times a
subsitute 7 for a
7^3=7 times 7 times 7
7^3=343
Answer:
\/
Step-by-step explanation:
▪Picture 1. x = 28
-
▪Picture 2. I don't know what in trying to solve.
▪Picture 3.
•ABC = 50
•DEF = 95
•GHI = 65
•JKL = 55
▪Picture 4. I dont know how to do that
