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natta225 [31]
3 years ago
11

Which ordered pairs are solutions to the equation?

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
D.
y=2x+5
Sub in one pair (5,15)
15=2(5)+5
15=10+5
15=15 [Correct]
AND
9=2(2)+5
9=4+5
9=9 [Correct]
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Elden [556K]
1) he is not reasonable because pounds per feet would mean you would do 7.3/14.6 which is a decimal

hope this helped :)
7 0
3 years ago
Help asap
PSYCHO15rus [73]

Answer:

27 & 72

Step-by-step explanation:

3*24=72 and 3*9=27 so they are both divisible by 3 and also if you subtract 24 from 72 you get 45. get it now?

4 0
2 years ago
Read 2 more answers
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
What is the domain of this function?
Luda [366]
A

Explanation-
Domain is the X, which is also independent. So you look at the first circle, or in more detail, the circle that has arrows pointing AWAY from it.
4 0
2 years ago
A chemist is mixing one solution that is 32% sodium and another solution that is 12% sodium how many liters of each type should
Brut [27]
In order to solve the amount of each solution, we need to set up equations. We do as follows:

Let x = solution with 32% sodium
      y = solution with 12% sodium

Overall balance
x + y = 50

Component balance
.32x + .12y = 50(.20) =10

Solving simultaneously,

x = 20
y = 30

Hope this answers the question. Have a nice day.
6 0
3 years ago
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