Answer:
What is the normal force on the object (draw a diagram if needed)
784 N
How much force is required to get the object to start to move from rest (max static friction)?
470.4 N
When the object starts moving, what is the force of kinetic friction?
274.4 N
If the moving object has a tension force of 300N to the right pulling it, what is the net force on the object in the horizontal direction? 784 N
What is the acceleration (with direction) of the object based on your answer for part d? Remember that a = net force/m.
Explanation:
Explanation:
(a) From E=
r
2
k
e
Q
Q=
k
e
Er
2
=
(8.99×10
9
N⋅m
2
/C
2
)
(8.90×10
2
N/C)(0.750m)
2
=5.57×10
−8
C
But Q is negative since
E
→
points inward, so
Q=−5.57×10
−8
C=−55.7nC
(b) The negatve charge has a spherically symmetric charge distribution, concentric with the spherical shell
Answer:
A freely suspended magnet comes to rest along the N-S direction.
Explanation:
-Irrespective of direction of suspension, the bar eventually comes to rest at earth's N-S direction.
-Bar end that points to Earth's north is called the <em>North Pole</em>. Bar end that point's to earth's south is called the <em>South pole</em>.
-The reason for this default positioning is called the Directive Property. This is because earth acts as an external magnetic field.
