Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean 
and standard deviation 
Sample size, n = 37
Standard Deviation =
P(taxi and takeoff time will be less than 320 minutes)
Calculation the value from standard normal z table, we have,
0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
Answer:
tan²x + 1 = sec²x is identity
Step-by-step explanation:
* Lets explain how to find this identity
∵ sin²x + cos²x = 1 ⇒ identity
- Divide both sides by cos²x
∵ sin x ÷ cos x = tan x
∴ sin²x ÷ cos²x = tan²x
- Lets find the second term
∵ cos²x ÷ cos²x = 1
- Remember that the inverse of cos x is sec x
∵ sec x = 1/cos x
∴ sec²x = 1/cos²x
- Lets write the equation
∴ tan²x + 1 = 1/cos²x
∵ 1/cos²x = sec²x
∴ than²x + 1 = sec²x
- So we use the first identity sin²x + cos²x = 1 to prove that
tan²x + 1 = sec²x
∴ tan²x + 1 = sec²x is identity
Answer:
17 acres
Step-by-step explanation:
9 acres + 8 acres = 17 acres, if that wasn't what the question meant please let me know and I'll change the answer or try to help clear confusion.
Answer: 61,750 miles
Step-by-step explanation:
Given : The p-value of the tires to outlast the warranty = 0.96
The probability that corresponds to 0.96 from a Normal distribution table is 1.75.
Mean : 
Standard deviation : 
The formula for z-score is given by : -
Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.
May is the 10th month after july
