here, 7 cellphone,9 Tv, 12airconditioners = 8723
5 cellphone,7 Tv, 12airconditioners = 6523
or, 7,9,12=8723
-5,7,9=6523
______________
2,2,3=2191
then,
to make 4 cellphone , 4 tv set , 6 air conditioners add twice the answer ,
2,2,3=2191
+2,2,3=2191
____________
4,4,6=4382
hence,
the price of 4 cellphone , 4 tv set and 6 air conditioners is 4382 #
solved by
<h3> pratik</h3>
Answer:
whats the problem
Step-by-step explanation:
Answer:

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:


We can find the probability of interest using the normal standard table and with the following difference:

Step-by-step explanation:
Let X the random variable who represent the expense and we assume the following parameters:

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:


We can find the probability of interest using the normal standard table and with the following difference:

Answer:
proportion used: 7/20
7emails were from the same person
Step-by-step explanation:
35/100= 7/20
7/20 of 20
20/20=1
1x7= 7