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3 years ago

PLEASE HELP Which of the following inequalities is true according to the number line?

Mathematics

1 answer:

Svetach [21]3 years ago

3 0

Answer:

A ≥ D

Step-by-step explanation:

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Graph g(x)=2cosx .

MArishka [77]

Answer:

we can draw the graph of cosine with amplitude 2.

Step-by-step explanation:

In the given function g(x) = 2cosx we know the following parameters which are helpful to draw the graph.

Its a cosine graph given in the form of y = acos(Bx + c) + d

Here a is amplitude, period = $\frac{2\pi }{B}$ , c = phase shift, d = vertical shift

We know a = 2, B = $\frac{2\pi }{1}$ , c = 0, d = 0.

6 0

3 years ago

Simplify The Expression 2y - y + 4 + y y=3

Brut [27]

-0.5

Step-by-step explanation:

um bc it is the answer

7 0

3 years ago

25 POINTS Lines a,b,c, and d are in the same plane. Line a is parallel to line c. Lines d and c are perpendicular to line d. Bas

polet [3.4K]

Assuming that the actual question reads lines b and c are perpendicular to line d

we are given that c is perpendicular to line d and parallel to line a. Since b is also perpendicular to line d, a b and c must all be parallel (draw it out will make a lot more sense)

So b is also parallel to line a

5 0

4 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

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6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

3 years ago

The digit 3 in which number represents a value of 0.030.030, point, 03?

pickupchik [31]

Answer:

The last 3

Step-by-step explanation:

Since it's. 030 and nothing after that

8 0

3 years ago