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Stels [109]
3 years ago
14

I need help with this math problem.

Mathematics
2 answers:
storchak [24]3 years ago
8 0
 p     r
10   18
12   16
14   14
16   12
mars1129 [50]3 years ago
5 0
14= 14
16=12
I hope I helped

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What is the product of (1.9*10^-3)(2*10^4)
RoseWind [281]

Answer:

to solve use the distributive property and multiply

Step-by-step explanation:

I'm sorry I do not have the product

4 0
3 years ago
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Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Check all that apply.
jonny [76]
First, we find the slope of the given line.

<span>3x − 4y = 7

-4y = -3x + 7

y = (3/4)x - 7/4

The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.

Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),

We use the point-slope form of the equation of a line.

y - y1 = m(x - x1)

y - (-2) = (3/4)(x - (-4))

y + 2 = (3/4)(x + 4)     <---- check option E. Is the fraction 3/4 not there?

y + 2 = (3/4)x + 3

y = (3/4)x + 1

4y = 3x + 4

3x - 4y = -4    <------ this is choice B.
</span>
8 0
3 years ago
I need help ASAP!! 13 points
OleMash [197]

Answer:

The correct answer is H

Step-by-step explanation:

1/4 of a wall in 2/3 of an hour is 40 min

so a wall takes 160 min which is 2 hours and 40 min

so 3 walls takes 8 hours

6 0
3 years ago
Read 2 more answers
Question is in the picture<br>please help
LiRa [457]

When given the graph of a function, the domain would include all the points that there is a graph. The strategy is to find what <em>is not</em> included.

What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

At x = 4 there is an unfilled (or open) circle and that means we exclude 4.

At x = 5 there is a filled circle so we include 5.

Now we refine our domain for the endpoints.

x ≤ -3, -1 < x < 4, x ≥ 5 is our domain.

The problem gives us intervals, and we gave it in inequalities. When we include an endpoint we use brackets - [ and } and when we exclude and endpoint we use parentheses - ( and ). Let's go back to x ≤ -3. Anything less works, and -3 is included (closed circle). That interval is (-∞, -3]. Next is the piece between -1 and 4. Since both are excluded, (-1,4) is our interval. We include 5 to write x ≥5 as the interval [5,∞).

Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

5 0
3 years ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b
goblinko [34]
So 4 inches diameter result the radius is 4/2 = 2 inches 

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volume = area of base *height 

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed 

hope this will help you 
3 0
3 years ago
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