Step-by-step explanation:
m and n are both located on the number line and are on the left of 0.
Therefore m and n are both negative reals.
m¹³ * n⁵
= (-)¹³ * (-)⁵
= (-) * (-)
= (+)
The answer is positive.
Answer:
2
Step-by-step explanation:
Step 1. <em>Find a coterminal angle that falls be 0 and 2π.
</em>
Remember that cscθ is a periodic function. It repeats every 2π radians.
If n is an integer, cscθ = csc(θ ± 2πn)
csc(17π/6) = csc(12π/6 + 5π/6)
= csc(2π + 5π/6)
= csc(5π/6)
Step 2. <em>Use the unit circle to evaluate cscθ.
</em>
cscθ = 1/sinθ
Let θ = 5π/6
In a unit circle (below), the sine of an angle is y.
sinθ = ½
cscθ = 1/sinθ
= 1/(½)
= 2
<h3>
Answer: B) 60</h3>
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Explanation:
Whenever the angle theta is between 0 and 90, the reference angle is exactly that value.
It's only when you get to other quadrants is when things get a bit tricky. Right now we're in quadrant 1, often written as Q1.
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Extra info:
- If theta is between 90 and 180, then the reference angle is 180-theta. This region is Q2
- If theta is in quadrant 3, between 180 and 270, then the reference angle is theta-180. The order of subtraction is important since x-y is the not the same as y-x.
- Lastly, if theta is between 270 and 360 (in Q4), then the reference angle is 360-theta.
- As you can see, we have four quadrants starting with Q1 in the upper right corner. Then we move counterclockwise to get Q2,Q3 and Q4.
To draw a histogram, you need two axes. The horizontal axis is the day and the vertical axis is the number of text messages. For the first day, there are 20 text messages. This is represented by a bar starting from the horizontal axis labeled Day 1 going up to the point where the vertical axis indicates 20 text messages. This is done for the rest of the data. Afterwards, a line is drawn from the vertex of the axes connected to the top of the first bar. Then from the top of the first bar, a line connects it to the top of the next bar. This is done for all the bars before producing a histogram.
Answer:
the answer is d
Step-by-step explanation:
