Plz help it’s important
1 answer:
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So, she has 3hrs to grade all papers, for 35 students.. alrite.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
=
[ 2a₁ + (n - 1)d ]
where a₁ is the initial value and d the common difference
Given
=
[ 10 + (n - 1)3 ]
Then by comparison
2a₁ = 10 ( divide both sides by 2 )
a₁ = 4 ← initial value
and d = 3 ← common difference
Thus
=
[ 10 + (7 × 3) ]
= 4(10 + 21)
= 4 × 31
= 124